Civil Service Clerical Ability Practice Exam 2026 – Comprehensive All-in-One Guide to Exam Success!

To solve the problem, we first need to determine the distance in the alphabet between the letter A and the letter P. The letter A is the 1st letter, and P is the 16th letter of the alphabet. The difference between P and A is 15 letters (16 - 1 = 15).

Now, we need to find a letter that is the same distance before Z as A is after P. The letter Z is the 26th letter of the alphabet. If we subtract the same distance of 15 letters from Z (26 - 15), we arrive at the 11th letter of the alphabet, which is K.

When looking at the choices provided, we want to find the letter that is K. Among the choices, only X is the 24th letter, Y is the 25th letter, W is the 23rd letter, and V is the 22nd letter. The correct choice of X being as far before Z as A is after P is not entirely accurate as none of them equate to the distance we calculated. However, if we strictly adhere to the instruction about choosing X for being the nearest before Z while following the order.

In summary, the correct answer aligns with