Civil Service Clerical Ability Practice exam

To determine the correct letter that is as far before J in the alphabet as K is after B, we first need to establish the distance between K and B. The letter K is the 11th letter of the alphabet, and B is the 2nd letter. The distance between them is calculated as: 11 (K) - 2 (B) = 9 letters. Now, we need to find a letter that is 9 letters before J. J is the 10th letter, so we subtract 9 from 10 to find the required letter: 10 (J) - 9 = 1. The 1st letter of the alphabet is A. Therefore, A is 9 letters before J, just as K is 9 letters after B. This reasoning confirms that A is the correct answer, as it fulfills the condition provided in the question.